Card rules · 2026-10-29
Why Three Available Pairs Do Not Make a Six-Card Result
Use an ordinary best-five-of-seven teaching rule. The shared cards are K♣, K♦, Q♥, Q♠ and 2♣; the private cards are 3♥ and 3♦. An example built from these cards contains three pairs in…
Use an ordinary best-five-of-seven teaching rule. The shared cards are K♣, K♦, Q♥, Q♠ and 2♣; the private cards are 3♥ and 3♦. An example built from these cards contains three pairs in the seven-card pool, but the result must contain only five cards.
Choose the strongest five
The selected hand is K♣–K♦–Q♥–Q♠ plus one 3. It contains kings and queens with a three as the fifth card. Both threes cannot join those four cards because that would make six.
The private pair has not disappeared
Both threes remain part of the available pool. Only one is needed for the strongest five-card selection. Either three gives the same rank result under a rule where suits do not break this tie.
“Three pairs” describes the larger pool, not a standard five-card hand category. Keep the available cards separate from the evaluated hand when writing the explanation. This example assumes ordinary high-hand ranking and unrestricted best-five selection; another selection rule would require a fresh evaluation.
Change the third pair and select again
Replace the private threes with A♥ and A♦, keeping the same board. The best five now contain aces, kings and one queen. The queens no longer supply the second pair because the newly available aces are higher. Always select from all seven again; naming two pairs on the board does not reserve those pairs permanently in the final five.